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How To Beat The Casino Using Side Bets in Blackjack- Lucky Lucky

You have to work out what things you want to count, this means looking at "Effect of Removal" etc. Use similar logic for other hands for trips subtract suited trips and straights subtract SF. That's what I assumed when writing the last paragraph. One way is to develop a spreadsheet. Then you need to collate the results based on the counts. Straight flush There are 4 suits and 12 ways to get a straight A23, , QKA i. It would take ages to analyse every combination of 30 cards, which is why you need to develop a method of running simulations and look for patterns. Personally I just learnt, looked up various algorithms etc. RSS Feed. I'm struggling a little with the logic behind calculating this. I believe I misled you when I said "30 random" cards. A thru Q can have a straight For each one there are 8 ways to get each card. Typically you have to narrow down the numbers e. I posted the above whilst you were posting your original reply. Thank you, that is a great explanation and I am going to get coding on putting this in action. The aim is to detect when a sidebet becomes in the player's advantage. I really appreciate your time and effort helping me with this. As a variation on the above, how would the outcomes be calculated in the event of a partial deck? I'm guessing it would be based on having a large number of one suit having gone, or perhaps a large number of specific ranks. Thank you once again for your detailed and useful response. Consider the eight decks but you number every card; so deck 1's Ace of Diamonds is 1Ad, etc. Thank you for the clarification regarding that. Thanks once again for your answer. Thank you for clarifying this and all your help. Kind Regards, Phoenix. There are some ideas by others of how to categorise poker hands rather than running every combination. I mean 30 cards that I am aware of but they are randomly taken from the 8-decks. I think I've made some progress since I posted this. Most Active Forum Threads Down and out with the Rectangle inscribed in{/INSERTKEYS}{/PARAGRAPH} Joined: Jun 17, Threads: 30 Posts: Thanks for this post from:. If the cards are 30 random then it doesn't make any difference. November 1st, at AM permalink. You need to develop a method of "counting", something you might use at the table. I'm going to get back to my program now and get this finished off. In this case create a spreadsheet where you can enter the cards gone, calculate the deck left, and work through all the hands that can be made from the modified deck. Joined: Oct 31, Threads: 1 Posts: 6. If the cards are specific i. The second card has to be the same now there are only 7 left , The third card has to be the same now there are only 6 left. I'm a programmer by trade so not afraid to get my hands dirty : Thanks, PQ. For example, if 30 random cards had been dealt and discarded so remain , how would I apply the same to calculate the updated probabilities in the case of Suited Three of a Kind for example? There are two scenarios I see. The original page is here. Consider "Version 6" with 8 decks. I have a card ex: Ace of Diamonds How many other cards match my card? If you're getting into developing a method to count cards and detect when the bet might be positive, then that probably gets complicated. Of course, a forum may be the wrong place to try to glean such information, but if you happened to know of any useful guides to get me started I would appreciate it. Of course, for 3 cards there are 6 permutations as order doesn't matter - I was being a bit slow then! {PARAGRAPH}{INSERTKEYS}Recommended online casinos. There's a lot of code to develop, creating random shoes and you'll then code what the spreadsheet would hae done. October 31st, at AM permalink. I've written some code already to calculate the chance of a Suited Three of a Kind, but it's returning exactly twice as many outcomes as per the formula you pointed out. Suited three of a kind can be any of 52 cards, there are 8 or each card e. So I'd like to programatically calculate how the odds differ dependent upon the remaining cards. I know some people e. Then you also need to develop a good random number generator and method to shuffle the cards.